Identify the compound `'Y'` in the following sequency of reaction
`HC-=CH overset((i) O_(3))underset((ii) H_(2)o_(2) //Zn)rarr Xoverset(Zn//CH_(3)COOH)rarrY`

Options

A.
B.
C.
D. `CH_(3)COOH`

Explanation

To identify the compound 'Y' in the given sequence of reactions, we will follow the steps outlined in the reaction process.

### Step-by-Step Solution:

1. **Identify the Starting Compound:**
The starting compound is acetylene, represented as \( HC \equiv CH \).

2. **Ozonolysis Reaction:**
The first step involves ozonolysis of acetylene. Ozonolysis is a reaction where ozone (O₃) cleaves the carbon-carbon triple bond.
- The reaction can be represented as:
\[ HC \equiv CH + O_3 \rightarrow \text{Ozonide} \]
- The ozonide will then break down into two carbonyl compounds (aldehydes) upon hydrolysis:
\[ \text{Ozonide} + H_2O \rightarrow H_2C=O + H_2C=O \]
- Therefore, we obtain two molecules of formaldehyde (methanal), \( H_2C=O \).

3. **Reduction Step:**
The next step involves the reduction of the carbonyl compounds using zinc (Zn) and acetic acid (CH₃COOH).
- The reaction can be represented as:
\[ 2 H_2C=O + Zn/CH_3COOH \rightarrow \text{Reduction Products} \]
- Each formaldehyde molecule will be reduced to an alcohol. The reduction of formaldehyde leads to the formation of methanol:
\[ H_2C=O + H_2 \rightarrow CH_3OH \]
- Since we have two molecules of formaldehyde, we will get two molecules of methanol.

4. **Final Product:**
The final product 'Y' after the reduction is:
\[ Y = CH_3OH \]
This indicates that 'Y' is methanol.

### Conclusion:
The compound 'Y' is methanol (CH₃OH).

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