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In Young's double slit experiment the co...

In Young's double slit experiment the coherent sources are 1.5 mm apart and the fringes are obtained on a screen at a distance 2.5 m from the plane of the sources. If the sources is illuminated with a light of 589.3 nm wavelength , find the number of fringes in the interference pattern thus formed on the screen. Total length of the fringes are `4.9 xx 10 ^(-3)` m.

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Knowledge Check

  • In Young's double slit experiment the two slits are d distance apart. Interence pattern is observed on a screen at a distance D from the slits. A dark fringe is observed on the screen directly opposite to one of the slits. The wavelength is

    A
    `(D^(2))/(2d)`
    B
    `(d^(2))/(2D)`
    C
    `(D^(2))/(d)`
    D
    `(d^(2))/(D)`

  • In Young's double slit experiment the distance between the slits is d. An interference fringe is obtained on a screen placed at a distance D from the slits . A dark band is noticed just opposite to one of the slits. The wavelength of the light used is

    A
    `D^(2)/(2d)`
    B
    `d^(2)/(2d)`
    C
    `D^(2)/(d)`
    D
    `d^(2)/(D)`

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    B
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