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In Young's double slit experiment the di...

In Young's double slit experiment the distance of the screen from the plane of the slits is 1.0 m. The wavelength of light used and width of the fringe are 6000 Å and 2 mm respectively.
Distance between the slits is

A

0.5 mm

B

0.4 mm

C

0.2 mm

D

0.3 mm

Text Solution

Verified by Experts

The correct Answer is:
D
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In Young's double slit experiment angular width of a fringe formed on a distant screen is 0.1^(@) . The wavelength of the light used in the experiment is 6000 Å. What is the distance between the two slits ?

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Knowledge Check

  • In Young's double slit experiment the distance of the screen from the plane of the slits is 1.0 m. The wavelength of light used and width of the fringe are 6000 Å and 2 mm respectively. If the wavelength of the light used is 4800 Å, the width of the fringe will be

    A
    1.6 mm
    B
    2.2 mm
    C
    2.0 mm
    D
    1.8 mm

  • In Young's double slit experiment the distance between the two slits is d and wavelength of the light used is lambda . The angular width of the fringe

    A
    `(d)/(lambda)`
    B
    `(lambda)/(d)`
    C
    `(2lambda)/(d)`
    D
    `(lambda)/(2d)`

  • If young' s double slit experiment is performed using white light, then

    A
    the central fringe will be white
    B
    no fringe will be completely dark
    C
    the fringe adjacent to the central one will be red
    D
    the fringe adjacent to the central one will be violet

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    In Young's double slit experiment the separation d between the slits is 2 mm the wavelength lambda of the light used is 5896 Å and distance D between the screen and slits is 100 cm. It is found that the angular width of the fringes is 0.20^(@) . To increase the fringe angular width to 0.21^(@) (with same lambda and D ) the separation between the slits needs to be changed to

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