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If the equation of a circle is lambda x^...

If the equation of a circle is `lambda x^(2) + (2 lambda - 3)y^(2) - 4x + 6y - 1 = 0`, then the coordinates of centre are -

A

`((2)/(3), -1)`

B

`((4)/(3), -1)`

C

`(-(2)/(3), 1)`

D

`((2)/(3), 1)`

Text Solution

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The correct Answer is:
A
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