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If the equation of a circle is lambda x^...

If the equation of a circle is `lambda x^(2) + (2 lambda - 3)y^(2) - 4x + 6y - 1 = 0`, then the coordinates of centre are -

A

`((2)/(3), -1)`

B

`((4)/(3), -1)`

C

`(-(2)/(3), 1)`

D

`((2)/(3), 1)`

Text Solution

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The correct Answer is:
A
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Knowledge Check

  • The point (2, -1) ________ the circle x^(2) + y^(2) - 4x + 6y + 8 = 0 .

    A
    lies inside
    B
    lies on
    C
    lies outside
    D
    is centre of

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    A
    4
    B
    41
    C
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    D
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