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The value of gamma=C(P)/C(V) for a gas i...

The value of `gamma=C_(P)/C_(V)` for a gas is given by `gamma=1+2/f` where f is the number of degrees of freedom of a molecule of a gas
What is the ratio of `(gamma_("monoatomic"))/(gamma_("diatomic"))` ?

A

`25/21`

B

`21/25`

C

`5/7`

D

`3/5`

Text Solution

AI Generated Solution

The correct Answer is:
To find the ratio of \(\frac{\gamma_{\text{monoatomic}}}{\gamma_{\text{diatomic}}}\), we will first calculate the values of \(\gamma\) for both monoatomic and diatomic gases using the given formula \(\gamma = 1 + \frac{2}{f}\). ### Step 1: Determine the degrees of freedom for monoatomic and diatomic gases - For a **monoatomic gas**, the degrees of freedom \(f\) is 3 (translational motion in x, y, and z directions). - For a **diatomic gas**, the degrees of freedom \(f\) is 5 (3 translational + 2 rotational). ### Step 2: Calculate \(\gamma\) for monoatomic gas Using the formula: \[ \gamma_{\text{monoatomic}} = 1 + \frac{2}{f_{\text{monoatomic}}} \] Substituting \(f_{\text{monoatomic}} = 3\): \[ \gamma_{\text{monoatomic}} = 1 + \frac{2}{3} = 1 + 0.6667 = \frac{5}{3} \] ### Step 3: Calculate \(\gamma\) for diatomic gas Using the formula: \[ \gamma_{\text{diatomic}} = 1 + \frac{2}{f_{\text{diatomic}}} \] Substituting \(f_{\text{diatomic}} = 5\): \[ \gamma_{\text{diatomic}} = 1 + \frac{2}{5} = 1 + 0.4 = \frac{7}{5} \] ### Step 4: Calculate the ratio \(\frac{\gamma_{\text{monoatomic}}}{\gamma_{\text{diatomic}}}\) Now we can find the ratio: \[ \frac{\gamma_{\text{monoatomic}}}{\gamma_{\text{diatomic}}} = \frac{\frac{5}{3}}{\frac{7}{5}} = \frac{5}{3} \times \frac{5}{7} = \frac{25}{21} \] ### Final Answer Thus, the ratio of \(\frac{\gamma_{\text{monoatomic}}}{\gamma_{\text{diatomic}}}\) is: \[ \frac{25}{21} \]

To find the ratio of \(\frac{\gamma_{\text{monoatomic}}}{\gamma_{\text{diatomic}}}\), we will first calculate the values of \(\gamma\) for both monoatomic and diatomic gases using the given formula \(\gamma = 1 + \frac{2}{f}\). ### Step 1: Determine the degrees of freedom for monoatomic and diatomic gases - For a **monoatomic gas**, the degrees of freedom \(f\) is 3 (translational motion in x, y, and z directions). - For a **diatomic gas**, the degrees of freedom \(f\) is 5 (3 translational + 2 rotational). ### Step 2: Calculate \(\gamma\) for monoatomic gas Using the formula: ...
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Knowledge Check

  • The ratio gamma((C_(P))/(C_(V))) for iner gases is

    A
    1.33
    B
    1.66
    C
    2.13
    D
    1.99
  • If gamma is the ratio of specific heats of a perfect gas, the no. of degrees of freedom of a molecule of the gas is

    A
    `25((gamma-1))/(2)`
    B
    `9((gamma-1))/(2)`
    C
    `(3gamma-1)/(2gamma-1)`
    D
    `(2)/(gamma-1)`
  • Each molecule of a gas has f degrees of freedom. The ratio gamma for the gas is

    A
    `1+(f)/(2)`
    B
    `1+(1)/(f)`
    C
    `1+(2)/(f)`
    D
    `1+((f-1))/(3)`
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