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The strength of the magnetic field in a ...

The strength of the magnetic field in a long solenoid having 5000 turns per meter is `3.14x 10^(-2)T`. The current flowing through the solenoid is

A

`2 A`

B

`3 A`

C

`4 A`

D

`5 A`

Text Solution

Verified by Experts

The correct Answer is:
D

`B=mu_0nI therefore I=B/(mu_0n) therefore I=(3.14 xx 10^(-2))/(4pi xx 10^(-7)xx 5 xx 10^(3))=5A`
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Knowledge Check

  • The magnetic field at a point on the axis of a long solenoid having 5 turns per cm length when a current of 0.8 A flows through it is

    A
    `5.024xx10^(-8) Wb//m^(2)`
    B
    `6.024xx10^(-8)Wb//m^(2)`
    C
    `7.024xx10^(-8) Wb//m^(2)`
    D
    `8.024xx10^(-8) Wb//m^(2)`
  • The strength of magnetic field inside a long current-carrying straight solenoid is:

    A
    more at the ends than at the centre
    B
    minimum in the middle
    C
    same at all points
    D
    found to increase from one end to the other
  • The magnetic field on the axis of a long solenoid having n turns per unit length and carrying a current is

    A
    `mu_(0)ni`
    B
    `mu_(0)n^(2)i`
    C
    `mu_(0)ni^(2)`
    D
    none of these
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