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If OA and OB are two perpendicular chord...

If `OA and OB` are two perpendicular chords of the circle `r = a cos theta + b sin theta` epassing through origin, then the locus of the mid point of `AB` is :

A

`x^(2)+y^(2)=a+b`

B

`x=(a)/(2)`

C

`x^(2)-y^(2)=a^(2)-b^(2)`

D

`y=(b)/(2)`

Text Solution

Verified by Experts

The correct Answer is:
B, D
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