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CH3 CH=CHCHO is oxidised to CH3 CH=CHCOO...

`CH_3 CH=CHCHO` is oxidised to `CH_3 CH=CHCOOH` using :

A

Alkaline `KMnO_(4)`

B

Selenium dioxide

C

Ammoniacal `Ag NO_(3)`

D

All

Text Solution

Verified by Experts

The correct Answer is:
C
`CH_(3) CH = CHCHO + 2[Ag (NH_(3))_(2)]^(+) rarr`
`2 Ag + 4NH_(3) + CH_(3) CH = CHCOOH + H_(2) O`
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