Home
Class 12
CHEMISTRY
In the following reaction order , B is ...

In the following reaction order , B is
`CH_(3)CH_(2)COOH overset (P//Br_(2)) to A overset (alc KOH) underset (H^(+)) to B`

A

`CH_(2)=CH-COOH`

B

`CH_(2)-underset(Br)underset(|)(CH)-COOH`

C

`CH_(3)CH_(2)COBr`

D

`CH_(3)CH_(2)CH_(2)OH`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will analyze the reactions taking place in the given sequence. ### Step 1: Identify the starting compound The starting compound is **CH₃CH₂COOH**, which is propanoic acid (a carboxylic acid). **Hint:** Recognize the functional groups and structure of the starting compound. ### Step 2: Understand the first reaction The first reaction involves **CH₃CH₂COOH** reacting with **P/Br₂**. This is known as the **Hale–Volhard–Zelinsky (HVZ) reaction**. In this reaction, the alpha-hydrogen of the carboxylic acid is replaced by a bromine atom. **Hint:** Recall that in HVZ reaction, bromination occurs at the alpha position of carboxylic acids. ### Step 3: Perform the HVZ reaction In the HVZ reaction, the alpha-hydrogen (the hydrogen attached to the carbon adjacent to the carboxylic acid) is replaced by bromine. Thus, the product A formed from this reaction will be **CH₃CHBrCOOH**. **Hint:** Identify the position of the alpha-hydrogen and understand how it is replaced by bromine. ### Step 4: Identify the second reaction The next step involves treating product A (**CH₃CHBrCOOH**) with **alc KOH** (alcoholic potassium hydroxide) followed by hydrolysis. This step typically leads to an elimination reaction. **Hint:** Remember that alcoholic KOH promotes elimination reactions, leading to the formation of alkenes. ### Step 5: Perform the elimination reaction In the elimination reaction, the bromine atom and a hydrogen atom from the adjacent carbon are removed, resulting in the formation of a double bond. The product formed will be **CH₂=CHCOOH**, which is **acrylic acid**. **Hint:** Visualize the elimination process to see how the double bond is formed. ### Conclusion The final product B after the reactions is **CH₂=CHCOOH** (acrylic acid). **Final Answer:** Product B is **CH₂=CHCOOH** (acrylic acid). ---
To solve the problem step by step, we will analyze the reactions taking place in the given sequence. ### Step 1: Identify the starting compound The starting compound is **CH₃CH₂COOH**, which is propanoic acid (a carboxylic acid). **Hint:** Recognize the functional groups and structure of the starting compound. ### Step 2: Understand the first reaction ...
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • ALDEHYDES, KETONES AND CARBOXYLIC ACID

    A2Z|Exercise Assertion-Reasoning Questions|7 Videos

  • ALDEHYDES, KETONES AND CARBOXYLIC ACID

    A2Z|Exercise Section D - Chapter End Test|30 Videos

  • ALDEHYDES, KETONES AND CARBOXYLIC ACID

    A2Z|Exercise AIPMT/NEET Questions|43 Videos

  • ALCOHOLS, PHENOLS AND ETHERS

    A2Z|Exercise Section D - Chapter End Test|30 Videos

  • BIOMOLECULES

    A2Z|Exercise Section D - Chapter End Test|30 Videos

Similar Questions

Explore conceptually related problems

Complete the following reactions : CH_(3)CH_(2)Br overset(Alc . KOH)to

Complete the following by providing (A),(B),(C) and (D) : (i) CH_(3)CH_(2)CH_(2) OH overset(PBr)(to) (A) overset(alc.KOH)underset(Delta)(to) (B) overset(HBr)(to)(C) overset(NH_(3))(to) (D) (ii) CH_(3)CH_(2)CH_(2)I overset(alc.KOH)underset(Delta)(to)(A)overset(H^(+)//H_(2)O)(to) (B)overset(SOCI_(2))(to)(C) overset(H)underset(LiAIH_(4))(to) (D) (iii) CH_(3)CHBrCH_(3) overset(alc.KOH)underset(Delta)(to) (A) overset(HBr)underset("Peroxide")(to) (B) overset(Nal)underset("Acetone")(to) (C) overset(H)underset("Ether")(to) (iv) CH_(3)CH_(2)CH=CH_(2) overset(NBS)underset("Light")(to) (A) overset(alc. KOH)underset(Delta)(to)(B) overset(HBr)(to)(C) (v) CH_(3)CH_(2)MgBroverset(CH_(3)CHO //H_(2)O)(to) (A) overset(HBr)(to)(B) overset(alc.KOH)underset(Delta)(to)(C) (A) overset(NH_(3))(to) (B) overset(CHCI_(3)+KOH(alc.))(to)(C) overset(Na)underset(C_(2)H_(5)OH)(to) CH_(3)-underset(CH_(3))underset(|)CH-NHCH_(3) (viii) CH_(3)CH_(2)Br overset((i)(CH_(2))_(6)N_(4))underset((ii)H_(2)O //H^(+))(to) (A) overset(NaOH)(to)(B) overset((i)O_(3))underset((ii)Zn//HOH)(to)(A) +(C) overset(conc.NaOH)(to)(D)

Knowledge Check

  • End product of the following reaction is CH_(3)CH_(2)COOH overset(Cl_(2))underset(red P)to overset("alcoholic KOH")to

    A
    `CH_(3)underset(OH)underset(|)(C)HCOOH`
    B
    `underset(OH)underset(|)(C)H_(2)CH_(2)COOH`
    C
    `CH_(2)=CHCOOH`
    D
    `underset(Cl)underset(|)(C)H_(2)underset(OH)underset(|)(C)HCOOH`

  • What are A and B in the following sequence of reactions : CH_(3)CH_(2)COOHunderset(Br_(2))overset(P)rarrA, (ii) Aunderset((ii)H^(+))overset((i)Alc.KOH"excess")rarrB

    A
    `CH_(3)-underset(Br)underset(|)CH.COOH,CH_(2)=CHCOOH`
    B
    `CH_(3)CH_(2)COBr, CH_(2)=CHCOOH`
    C
    `underset(Br)underset(|)CH_(2)CH_(2)COOH,CH_(2)=CH.COOH`
    D

  • CH_(3)CH_(2)COOH overset(Cl_(2))underset("red P") to A overset("alc KOH") to B What is B?

    A
    `CH_(3)CH_(2)COCl`
    B
    `CH_(3)CH_(2)CHO`
    C
    `ClCH_(2)CH_(2)COOH`
    D
    `CH_(2)=CHCOOH`

    • Similar Questions

    Explore conceptually related problems

    CH_(3)CH_(2)COOH underset("red P")overset(Cl_(2))to A overset(Alc. KOH)to B What is B?

    The compound B is : CH_(3)CH_(2)COOH overset(Cl_(2))underset(red P)rarrAoverset(Alc. KOH)rarrB

    The compound A , B and C in the reaction sequence CH_(3) - CH_(2) OH overset(PBr_(3))to A overset(Alc. KOH) to B overset(Br_(2))to C are given by the set :

    The compound A , B and C in the reaction sequence CH_(3) - CH_(2) OH overset(PBr_(3))to A overset(Alc. KOH) to B overset(Br_(2))to C are given by the set :

    Identify C in the following reactions : CH_3 - CH = CH_(2) overset(HBr)(to) A overset(KOH "(alc.)")(to) B overset(HBr) underset(H_2O_2)(to) C

    Home
    Profile