Home
Class 11
CHEMISTRY
In the reaction Cr2 O7^(2-) 14 H^(+) + ...

In the reaction ` Cr_2 O_7^(2-) 14 H^(+) + 6e^(-) rarr 2 Cr^(3+) + 7 H_2O`, the equivalent weight fo `K_2 Cr_2 O_7` will be .

A

`M//6`

B

`M//3`

C

`M//12`

D

`M//9`

Text Solution

Verified by Experts

The correct Answer is:
A
`overset(+6)(C)r_(2)O_(7)^(2-) rarr 2 overset(+3)(C)r^(3+)`
There are 2 Cr atoms in `Cr_(2)O_(7)^(2-)`. Thus, we must calculate the change in oxidation numbers for two Cr atoms on both sides. Hence, the oxidation numbers decreases from `2(+6)=+12` to `2(+3)=+6`
Equivalent weight
`=("Formula weight (M)" ) /(("Total change in oxidation number of element" ),("oxidized"//"reduced per mole of compound"))`
`=M/6`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • REDOX REACTIONS

    R SHARMA|Exercise Follow-up Test 7|10 Videos

  • REDOX REACTIONS

    R SHARMA|Exercise Question Bank|26 Videos

  • REDOX REACTIONS

    R SHARMA|Exercise Follow-up Test 5|8 Videos

  • PURIFICATION AND CHARATERIZATION OF ORGANIC COMPOUNDS

    R SHARMA|Exercise Archives|38 Videos

  • SOME BASIC CONCEPTS OF CHEMISTRY

    R SHARMA|Exercise Archives|26 Videos

Similar Questions

Explore conceptually related problems

Consider the reaction : Cr_(2)O_(7)^(2-)+14H^(+)+6e^(-) rarr 2Cr^(3+)+7H_(2)O What is the quantity of electricity in coulombs needed to reduce 1 mol e of Cr_(2)O_(7)^(2-) ?

Consider the reaction : Cr_(2)O_(7)^(2-) + 14H^(+) + 6e^(-) to 2Cr^(3+) + 7H_(2)O What is the quantity of electricity in coulombs needed to reduce 1 mol of Cr_(2)O_(7)^(2-) ?

Knowledge Check

  • In acidic medium potassium dichromate acts as on oxidant according to the equation, Cr_(2) O + 14 H^(+) + 6e^(-)rarr 2Cr^(3+) + 7H_(2)O . What is the equivalent weight of K_(2) Cr_(2) O_(7) ? (mol. Wt. = M)

    A
    `M`
    B
    `M//2`
    C
    `M//3`
    D
    `M//6`

  • In the reaction: Cr_(2)O_(7)^(2-) + 14H^(o+) + 6I^(Ө) rarr2Cr^(3+) + 3H_(2)O + 3I_(2) Which element is reduced?

    A
    `Cr`
    B
    `H`
    C
    `O`
    D
    `I`

  • In the following reaction Cr_(2) O_(7)^(2-) + 14H^(+) + 6I^(-) rarr 2Cr^(3+) + 7H_(2)O + 3I_(2) Which element gets reduced ?

    A
    Cr
    B
    H
    C
    O
    D
    I

    • Similar Questions

    Explore conceptually related problems

    Consider the reaction Cr_(2)O_(7)^(2-)+14H^(+)6e^(-)rarr2Cr^(3+)+8H_(2)O What is the quantity of electricity in coulombs needed to reduce 1 mole of Cr_(2)O_(7)^(2) ?

    Consider the reaction : Cr_(2)O_(7)^(2-)+14H^(+)+6e^(-) to 2Cr^(3+)+7H_(2)O What is the quantity of electricity in coulombs needed to reduce 1 mole of Cr_(2)O_(7)^(2-) ions ?

    Consider the reaction, Cr_(2)O_(7)^(2-)+ 14H^(+) + 6e^(-) to 2 Cr^(3+) + 7H_(2)O What is the quantity of electricity in coulombs needed to reduce 1 mole of 2 Cr_(2)O_(7)^(2-) ? (Given 1F= 96500C)

    The value of n in the equation, Cr_(2)O_(7)^(2-) +14 H^(+)+ne^(-) to 2Cr^(3+) + 7H_(2)O is :

    In reaction, Cr_(2)O_(7)^(2-)+14H^(+)+6I^(-) to 2Cr^(3+)+7H_(2)O+3I_(2) which element is reduced ?

    Home
    Profile