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The most common oxidation number exhibit...

The most common oxidation number exhibited by `C` is

A

`+4`

B

`+2`

C

`0`

D

`-4`

Text Solution

Verified by Experts

The correct Answer is:
A
For element `C`, the `+4` oxidation state is more thermodynamically stable than is the `+2` state.
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Knowledge Check

  • The most common oxidation state exhibited by all lanthanoids is

    A
    `+1`
    B
    `+2`
    C
    `+3`
    D
    `+4`

  • The most common oxidation state exhibited by the d-block elements (and why) in the 3d series is

    A
    `+3`, due to the participation of ns and np electrons
    B
    ` +3`, due to the participation of ns and (n – 1)d- electrons
    C
    `+2`, due to the participation of ns electrons
    D
    ` +2`, due to the participation of (n – 1)d unpaired electrons

  • The largest oxidation number exhibited by depends on its outer electronic configuration. Which of the following outer electronic configuration the other will exhibit largest oxidation number?

    A
    `3d^(1) 4s^(2)`
    B
    `3d^(3) 4s^(2)`
    C
    `3d^(5) 4s^(1)`
    D
    `3d^(5) 4s^(2)`

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    The largest oxidation number exhibited by an element depend on its outer electronic configuratoin with which of the following outer eletronic configuration the element will exhibit largest oxidation number ?

    The largest oxidation number exhibited by depends on its outer electronic configuration. Which of the following outer electronic configuration the other will exhibit largest oxidation number?

    The largest oxidation number exhibited by an element depends on its outer eletronic configuration. With which of the following outer electronic configurations the element will exhibit largest oxidation number ?

    Oxidation state/s exhibited by Ce is / are

    The most common oxidation explained as due to:

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