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Write down the acyclic isomers having th...

Write down the acyclic isomers having the molecular formula `C_3H_6O`.
Strategy: first calculate the degree of unsaturation or DBEs:
`DBE=(sumn(v-2))/(2)+1`
`=(3(4-2)+6(1-2)+1(2-2))/(2)+1=1`
This means that various acyclic isomers of `C_3H_6O` contain just one double bond, i.e., `C=C` or `C=O`, in the following skeletons:
`C-C-C-O,C-C-O-C,C-underset(O)underset(|)(C)-C`

Text Solution

Verified by Experts

(i). `CH_(2)=CH-CH_(2)-OH`
(ii). `CH_(3)CH=CH-OH`
(iii). `CH_(3)CH_(2)CH=O`
(iv). `CH_(2)=CH-O-CH_(3)`
(v). `CH_(2)=underset(OH)underset(|)(C)-CH_(3)`
(vi). `CH_(2)underset(O)underset(||)(C)CH_(3)`
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