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For the coagulation of 100mL of arseniou...

For the coagulation of `100mL` of arsenious sulphide solution `5mL` of `1MNaCl` is reqired. The coagulating power of `NaCl` is

A

`50`

B

`47.6`

C

`52.4`

D

`0.0476`

Text Solution

Verified by Experts

The correct Answer is:
B
We must calculate no. of millimoles of electrolyte that must be added to `1` litre of sol for coagulation.
`100mL` of sol requires `5mL` of `1M NaCl` .
Thus, `1000mL` will require
`(5)/(100)xx1000=50mL`
Total volume of system after addition of `50mL` of `1M NaCl`
solution is `1050mL` . Now we must calculate the new molarity of `NaCl` through dilution equation
`M_(i)V_(i)=M_(f)V_(f)`
`1xx50=M_(f)xx1050`
`M_(f)=(50)/(1050)=(5)/(105)molL^(-1)`
Concentration in millimoles per litre
`=(5)/(105)xx1000`
`=47.6`
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Knowledge Check

  • For the coagulation of 500mL of arsenious sulphide sol, 2mL of 1MNaCl is required. What is the flocculation value of NaCl ?

    A
    3
    B
    2
    C
    5
    D
    4

  • For the coagulation of 200mL of As_(2)S_(3) solution 10mL of 1 M NaCl is required. What is the coagulationg value (number of milimoles of solute needed for coagulation of 1 litre of solution) of NaCl .

    A
    200
    B
    100
    C
    50
    D
    25