The range of a projectile, thrown with an initial speed `u` at the angle of projection `15^(@)` is `R`. What will be the range if it is thrown with an initial speed `2u` at an angle `30^(@)` ?

Options

A. `4sqrt(3) R`
B. `2 sqrt(3) R`
C. `sqrtR`
D. `5sqrt(3) R`

Answer

A

Explanation

`R = (u^(2))/(g) sin 30^(@), R' = ((2u)^(2))/(g) sin 60^(@)`
`(R')/(R ) = 4(sin 60^(@))/(sin 30^(@)) = 4 sqrt(3)`
`R'=4sqrt(3)R`