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When a tuning fork A of frequency 100 Hz...

When a tuning fork `A` of frequency `100 Hz` is sounded with a tuning fork `B`, the number of beats per second is `2`. On putting some wax on the prongs of `B`, the number of beats per second becomes `1`. The frequency of the fork `B` is

A

`98 Hz`

B

`99 Hz`

C

`101 Hz`

D

`102 Hz`

Text Solution

Verified by Experts

The correct Answer is:
D
Possible frequency of `B: 100+-2 = 102 Hz` or `98 Hz`
Frequency of `A: 100 Hz`
When wax is used on `B, f_(b): downarrow`, beat frequency decreases, this is possible at `f_(B) = 102 Hz`
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