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The point P of a string is pulled up wit...

The point `P` of a string is pulled up with an acceleration `g`. Then the acceleration of the hanging disc (w.r.t ground) over which the string is wrapped, is

A

`(2 g)/3 darr`

B

`g/3 uarr`

C

`(4g)/3 darr`

D

`g/3 darr`

Text Solution

Verified by Experts

The correct Answer is:
D
`2mg-T=ma, TR=Ialpha`
`alpha=a/R,`solving `alpha=g/3`
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Knowledge Check

  • If block A is moving with an acceleration of 5ms^(-2) , the acceleration of B w.r.t. ground is

    A
    `5ms^(-2)`
    B
    `5sqrt(2)ms^(-2)`
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    `(mgd)/(3)`
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    `(-mgd)/(3)`
    C
    `(2)/(3)mgd`
    D
    `(-2)/(3)mgd`

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