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The potential energy function for the fo...

The potential energy function for the force between two atoms in a diatomic molecule is approximate given by `U(r) = (a)/(r^(12)) - (b)/(r^(6))`, where `a` and `b` are constants and `r` is the distance between the atoms. If the dissociation energy of the molecule is `D = [U (r = oo)- U_("at equilibrium")],D` is

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To find the dissociation energy \( D \) of the diatomic molecule given the potential energy function \( U(r) = \frac{a}{r^{12}} - \frac{b}{r^{6}} \), we will follow these steps: ### Step 1: Understand the Dissociation Energy The dissociation energy \( D \) is defined as the difference between the potential energy at infinity and the potential energy at equilibrium: \[ D = U(\infty) - U(r_{\text{eq}}) \] ...
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The potential energy function for the force between two atoms in a diatomic molecule is approximately given by U(x) =a/x^(12)-b/x^(6) where a and b are constant and x is the distance between the atoms. Find the dissoociation energy of the molecule which is given as D=[U(x- infty)-U_(at equilibrium)]

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The potential energy between two atoms in a molecule is given by U(x)= (1)/(x^(12))-(b)^(x^(6)) , where a and b are positive constants and x is the distance between the atoms. The atom is in stable equilibirum when

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The potential energy between two atoms in a molecule is given by, U_((x))=(a)/x^(12)-(b)/x^(6) , where a and b are positive constant and x is the distance between the atoms. The atoms is an stable equilibrium, when-

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The potential energy function for the force between two in a diatomic molecule can approximately be expressed as U(x)=(a)/(x^(12))-(b)/(x^(4)) , where a and b are positive constants, and x is the distance between the atoms. Answer the following question by selecting most appropriate alternative. The graph between force between the atoms [F(x)] vs x will be

The potential energy between two atoms in a molecule is given by U=ax^(2)-bx^(2) where a and b are positive constants and x is the distance between the atoms. The atom is in stable equilibrium when x is equal to :-

In a molecule, the potential energy between two atoms is given by U (x) = (1)/(x^(12)) -(b)/(x^(6)) . Where 'a' and 'b' are positive constants and 'x' is the distance between atoms. Find the value of 'x' at which force is zero and minimim P.E at that point.

Knowledge Check

  • The potential energy funtions for the force between two along in a distance molecule is approximatily given by U(x) = (a)/(x^(12)) - b)/(x^(6)) where a and b are constant and x is the distance between the aloms , if the discision energy of the molecale is D = [U(x = oo) - U atequlibrium ] , D is

    A
    `(b^(2))/(2a)`
    B
    `(b^(2))/(12a)`
    C
    `(b^(2))/(4a)`
    D
    `(b^(2))/(6a)`
  • The potential energy between two atoms in a molecule is given by U(x)= (1)/(x^(12))-(b)^(x^(6)) , where a and b are positive constants and x is the distance between the atoms. The atom is in stable equilibirum when

    A
    `x = 6sqrt((11a)/(5b))`
    B
    `x = 6sqrt((a)/(2b))`
    C
    `x =0`
    D
    `x = 6sqrt((2a)/(b))`
  • The potential energy between two atoms in a molecule is given by U=ax^(2)-bx^(2) where a and b are positive constants and x is the distance between the atoms. The atom is in stable equilibrium when x is equal to :-

    A
    `0`
    B
    `(2b)/(3a)`
    C
    `(3a)/(2b)`
    D
    `(3b)/(2a)`
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