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The potential energy function for the fo...

The potential energy function for the force between two atoms in a diatomic molecule is approximate given by `U(r) = (a)/(r^(12)) - (b)/(r^(6))`, where `a` and `b` are constants and `r` is the distance between the atoms. If the dissociation energy of the molecule is `D = [U (r = oo)- U_("at equilibrium")],D` is

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To find the dissociation energy \( D \) of the diatomic molecule given the potential energy function \( U(r) = \frac{a}{r^{12}} - \frac{b}{r^{6}} \), we will follow these steps: ### Step 1: Understand the Dissociation Energy The dissociation energy \( D \) is defined as the difference between the potential energy at infinity and the potential energy at equilibrium: \[ D = U(\infty) - U(r_{\text{eq}}) \] ...
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The potential energy function for the force between two atoms in a diatomic molecule is approximately given by U(x) =a/x^(12)-b/x^(6) where a and b are constant and x is the distance between the atoms. Find the dissoociation energy of the molecule which is given as D=[U(x- infty)-U_(at equilibrium)]

If potential energy function for the force between two atoms in a diatomic molecule is approximately given by U(x)=(a)/(x^(8))-(b)/(x^(4)) , where a and b are constants in standard SI units and x in meters. Find the dissociation energy of the molecule (in J). ["Take a "="4 J m"^(8) and b="20 J m"^(4)]

Knowledge Check

  • The potential energy funtions for the force between two along in a distance molecule is approximatily given by U(x) = (a)/(x^(12)) - b)/(x^(6)) where a and b are constant and x is the distance between the aloms , if the discision energy of the molecale is D = [U(x = oo) - U atequlibrium ] , D is

    A
    `(b^(2))/(2a)`
    B
    `(b^(2))/(12a)`
    C
    `(b^(2))/(4a)`
    D
    `(b^(2))/(6a)`

  • The potential energy between two atoms in a molecule is given by U(x)= (1)/(x^(12))-(b)^(x^(6)) , where a and b are positive constants and x is the distance between the atoms. The atom is in stable equilibirum when

    A
    `x = 6sqrt((11a)/(5b))`
    B
    `x = 6sqrt((a)/(2b))`
    C
    `x =0`
    D
    `x = 6sqrt((2a)/(b))`

  • The potential energy between two atoms in a molecule is given by U=ax^(2)-bx^(2) where a and b are positive constants and x is the distance between the atoms. The atom is in stable equilibrium when x is equal to :-

    A
    `0`
    B
    `(2b)/(3a)`
    C
    `(3a)/(2b)`
    D
    `(3b)/(2a)`

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