A siphon tube is used to remove liquid from a container as shown in fig. In order to operate the siphon tube, it must initially be filled with the liquid.
(i). Determine the pseed of the liquid through the siphon.
(ii). Determine the pressure at the point C.

Explanation

(i) Applyiing Bernoulli's equation at point A and D, we get
`P_(A)+(1)/(2)rv_(A)^(2)+rgy_(A)=p_(D)+(1)/(2)rv_(D)^(2)+rgy_(D)`
Assuming paturn for potential energy at the free surface, we have
`y_(A)=0,y_(D)=-(h+y)`
`p_(A)=p_(D)=p_(atm)v_(A)^(2)approx0,v_(D)=v`
`p_(atm)+0+0=p_(atm)+(1)/(2)rv^(2)=rg[-(h+y)]`
or `v=sqrt(2g(h+y))`
(ii) Applying Bernoulli's equation at A and C, we get
`p_(A)+(1)/(2)rv_(A)^(2)+rgy_(A)=p_(C)+(1)/(2)rv_(C)^(2)+rgy_(C)`
Here, `y_(C)=+H,v_(C)=v` (according to the continuity equation)
`p_(atm)+0+0=pC+(1)/(2)rv^(2)+rgh`
or `p_(atm)=pC+rg(h+y)+rgh`
or `pC=p_(atm)-rg(h+H+y)`