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30 kg ice at 0^@C and 20 g of steam at 1...

`30 kg` ice at `0^@C` and `20 g` of steam at `100^@C` are mixed. The composition of the resultant mixture is

A

`40 g` of water and `10 g` steam at `100^@C`

B

`10g` of ice and `40 g` of water at `0^@C`

C

`50g` of water at `100^@C`

D

`35 g` of water and `15 g` of steam at `100^@ C`

Text Solution

Verified by Experts

The correct Answer is:
A
`m_(s)L_(s) =(m_(ice)L_(ice) + m_(ice) s Delta theta)`
Where `m_(s)` = mass f steam condensed to rise temperature of ice to `100^@C` water.
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