100 g of water is supercooled to - `10^@C.` At this point, due to same disturbance mechanised or otherwise some of it suddenly freezes to ice. What will be the temperautre of the resultant mixture and how much mass would freeze ?`[s_w = 1 cal//g// .^@ C and L_(Fusion)^(w) = 80 cal//g]`
50 g of ice at 0^@C is mixed with 50 g of water at 80^@C . The final temperature of the mixture is (latent heat of fusion of ice =80 cal //g , s_(w) = 1 cal //g ^@C)
A copper calorimeter of mass 100g and temperature 30^(@)C contains water of mass 200 g and temperature 30^(@)C . If a pieceof ice of mass 40g and temperature 0^(@)C is added to it,what will be the maximum temperature of the mixture ? [c( copper ) = 0.1 cal // g.^(@)C, c ( water ) = 1 cal //g.^(@) C , L = 80 cal //g ]
What will be the final temperature when 150 g of ice at 0^@C is mixed with 300 g of water at 50^@C . Specific heat of water =1 cal//g//^@C . Latent heat of fusion of ice =80 cal//g .
One gram of ice at 0^(@)C is added to 5 gram of water at 10^(@)C . If the latent heat of ice be 80 cal/g, then the final temperature of the mixture is -
10 g of ice at 0^@C is mixed with 100 g of water at 50^@C . What is the resultant temperature of mixture
1 gram of ice at -10^@ C is converted to steam at 100^@ C the amount of heat required is (S_(ice) = 0.5 cal//g -^(@) C) (L_(v) = 536 cal//g & L_(f) = 80 cal//g,) .
Calculate the quantity of heat released during the conversion of10g of ice cold water ( temperature 0^(@)C ) into ice at the same temperature . ( Specific latent heat of freezing of water = 80 cal //g )
