Home
Class 11
PHYSICS
A calorimeter takes 200 cal of heat to r...

A calorimeter takes `200 cal` of heat to rise its temperature through `10^@C`. Its water equivalent in `gm` is

A

`2`

B

`10`

C

`20`

D

`40`

Text Solution

AI Generated Solution

The correct Answer is:
To find the water equivalent of the calorimeter, we can use the formula that relates heat absorbed, mass, specific heat, and temperature change. Here are the steps to solve the problem: ### Step-by-Step Solution: 1. **Understand the Given Information**: - Heat absorbed by the calorimeter, \( Q = 200 \) calories. - Temperature change, \( \Delta T = 10^\circ C \). 2. **Use the Formula for Heat Transfer**: The formula for heat transfer is given by: \[ Q = m \cdot s \cdot \Delta T \] where: - \( Q \) is the heat absorbed (in calories), - \( m \) is the mass (in grams), - \( s \) is the specific heat capacity (for water, \( s = 1 \) calorie/g°C), - \( \Delta T \) is the change in temperature (in °C). 3. **Substitute the Known Values**: Since we are considering the water equivalent, we can substitute the known values into the formula: \[ 200 = m \cdot 1 \cdot 10 \] 4. **Simplify the Equation**: This simplifies to: \[ 200 = 10m \] 5. **Solve for \( m \)**: To find \( m \), divide both sides by 10: \[ m = \frac{200}{10} = 20 \text{ grams} \] 6. **Conclusion**: The water equivalent of the calorimeter is \( 20 \) grams. ### Final Answer: The water equivalent of the calorimeter is **20 grams**.

To find the water equivalent of the calorimeter, we can use the formula that relates heat absorbed, mass, specific heat, and temperature change. Here are the steps to solve the problem: ### Step-by-Step Solution: 1. **Understand the Given Information**: - Heat absorbed by the calorimeter, \( Q = 200 \) calories. - Temperature change, \( \Delta T = 10^\circ C \). ...
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • CALORIMETRY

    NARAYNA|Exercise Level- I (H.W)|15 Videos
  • CIRCULAR MOTION

    NARAYNA|Exercise LEVEL II(H.W)|51 Videos

Similar Questions

Explore conceptually related problems

A calorimeter takes 400 cal of heat to rise its temperature through 10C .Its water equivalent in gm is N times10 then the value of N is

A copper sphere of 200 g mass is heated to raise its temperature to 160^(@)C and is released in water of mass I 00 g and temperature 10^(@)C in a copper calorimeter. If the mass of calorimeter is 50 g, what will be the maximum temperature of water? (Given: specific heat of copper = 0.1 " cal/g """^(@)C)

Knowledge Check

  • 100 ml of water at 20^(@)C and 100 ml of water at 40^(@)C are mixed in calorimeter until constant temperature reached. Now temperature of the mixture is 28^(@)C . Water equivalent of calorimeter is

    A
    50 J
    B
    104.5 J
    C
    `-24.2 J`
    D
    `209 J`
  • 75 gm of copper is heated to increase its temperature by 10^@ C . If the same quantity of heat is given to 'm' gm of water, to have same rise in temperature is (specific heat of copper = 420 J//Kg-^@ C ).

    A
    7.5 gm
    B
    5 gm
    C
    10 gm
    D
    25 gm
  • A calorimeter contains 10 g of water at 20^(@)C . The temperature falls to 15^(@)C in 10 min. When calorimeter contains 20 g of water at 20^(@)C , it takes 15 min for the temperature to becomes 15^(@)C . The water equivalent of the calorimeter is

    A
    5 g
    B
    10 g
    C
    25 g
    D
    50 g
  • Similar Questions

    Explore conceptually related problems

    A copper sphere of 200 g mass is heated to raise its temperature to 160^(@)C and is released in water of mass I 00 g and temperature 10^(@)C in a copper calorimeter. If the mass of calorimeter is 50 g, what will be the maximum temperature of water? (Given: specific heat of copper = 0.1 " cal/g """^(@)C)

    A copper sphere of 100 g mass is beated to raise its temperature to 100^@C g mass is heated to raise its temperature to 100^@C and is released in water of mass 195 g and teperature 20^@C in a copper calorimeter. If the mass of clorimeter is 50 g. what will be the maximum temperature of water? (Give : specific heat of copper = 0.1 cal // g^@C and specific heat of calrimeter =0.1 " cal / g "^@C

    A copper sphere of 100 g mass is beated to raise its temperature to 100^@C g mass is heated to raise its temperature to 100^@C and is released in water of mass 195 g and teperature 20^@C in a copper calorimeter. If the mass of clorimeter is 50 g. what will be the maximum temperature of water? (Give : specific heat of copper = 0.1 cal // g^@C and specific heat of calrimeter =0.1 " cal / g "^@C

    A calorimeter contains 400 gm of water at temperature of 5^@C . Then, 200 gm of water at a temperature of +10^@C and 400 gm of ice at temp. of -60^@C are added. Specific heat of ice =0.5 cal/gm. At equilibrium

    50 gm of copper is heated to increase its temperature by 10^(@)C. If the same quantity of heat is given to 10 gm of water, the rise in its temperature is (Specific heat of copper =420 Joule-kg^(-1)@C^(-1)