Home
Class 12
PHYSICS
The moment of inertia of a circular disc...

The moment of inertia of a circular disc of radius 2 m and mass 1 kg about an axis passing through the centre of mass but perpendicular to the plane of the disc is 2 kg-`m^(2)` . Its moment of inerti about an axis parallel to this axis but passing through the edge of the dics is (see the given figure).

A

`8kg-m^(2)`

B

`4kg-m^(2)`

C

`10kg-m^(2)`

D

`6kg-m^(2)`

Text Solution

Verified by Experts

The correct Answer is:
D
According to parallel axis theorem,

`l_(x'y')=l_(xy)+MR^(2)`
`=2+(1)(2)^(2)="6kg - m"^(2)`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • ROTATIONAL MOTION'

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise PRACTICE EXERCISE (Exercise 2 (MISCELLANEOUS PROBLEMS))|47 Videos

  • ROTATIONAL MOTION'

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise MHT CET Corner|35 Videos

  • ROTATIONAL MOTION'

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise MHT CET Corner|35 Videos

  • REFRACTION OF LIGHT

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise Exercise 2|25 Videos

  • SCALARS AND VECTORS

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise Exercise 2 (Miscellaneous Problems)|20 Videos

Similar Questions

Explore conceptually related problems

Calculate the moment of inertia of a disc of radius R and mass M, about an axis passing through its centre and perpendicular to the plane.

Calculate the moment of Inertia of a semicircular disc of mass M and radius R about an axis passing through its centre and perpendicular to its plane.

Knowledge Check

  • Moment of inertia of a uniform quarter disc of radius R and mass M about an axis through its centre of mass and perpendicular to its plane is :

    A
    `(MR^(2))/(2)-M((4R)/(3pi))^(2)`
    B
    `(MR^(2))/(2)-M(sqrt(2)(4R)/(3pi))^(2)`
    C
    `(MR^(2))/(2)+M((4R)/(3pi))^(2)`
    D
    `(MR^(2))/(2)+M(sqrt(2)(4R)/(3pi))^(2)`

  • The moment of Inertia of an incomplete disc of mas M and radius R as shown in figure about the axis passing through the centre and perpendicular to the plane of the disc is:

    A
    `(MR^(2))/2`
    B
    `(7MR^(2))/12`
    C
    `(7MR^(2))/6`
    D
    `(5 MR^(2))/12`

  • The moment of inertia of a uniform circular disc of radius R and mass M about an axis passing from the edge of the disc and normal to the disc is

    A
    `MR^(2)`
    B
    `1/2MR^(2)`
    C
    `3/2MR^(2)`
    D
    `7/2MR^(2)`

    • Similar Questions

    Explore conceptually related problems

    The moment of inertia of a circular disc of radius 2m and mass 1kg about an axis passing through its centre of mass is 2kg-m^(2) .Its moment of inertia about an axis parallel to this axis and passing through its edge in kg-m^(2)) is

    Calculate the moment of inertia of a ring of mass 2 kg and radius 50 cm about an axis passing through its centre and perpendicular to its plane

    The moment of inertia of a square plate of mass 4kg and side 1m about an axis passing through its centre and perpendicular to its plane is

    The moment of inertia of a uniform circular disc of radius R and mass M about an axis passing from the edge of the disc and normal to the disc is.

    The diameter of a thin circular disc of mass 2 kg is 0.2 m. Its moment of inertia about an axis passing through the edge and perpendicular to the plane of the disc is

    Home
    Profile