The moment of inertia of a circular disc of radius 2 m and mass 1 kg about an axis passing through the centre of mass but perpendicular to the plane of the disc is 2 kg-`m^(2)` . Its moment of inerti about an axis parallel to this axis but passing through the edge of the dics is (see the given figure).

Options

A. `8kg-m^(2)`
B. `4kg-m^(2)`
C. `10kg-m^(2)`
D. `6kg-m^(2)`

Answer

D

Explanation

According to parallel axis theorem,

`l_(x'y')=l_(xy)+MR^(2)`
`=2+(1)(2)^(2)="6kg - m"^(2)`