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In qualitive analysis , an organic c...

In qualitive analysis , an organic compound'A' is heated Dry `CuO ,CO_(2)` gas is liberated and `H_(2)O` is formed . The same compound 'A' when heated with ` Na_(2) O_(2)` , followed by boiling with `HNO_(3)` and ammonium molybdate gives yellow precipitate . Based on teh tests , the elements present in compound 'A' are __________.

A

C,H and N

B

`C,H and P`

C

C and P

D

C and H

Text Solution

Verified by Experts

The correct Answer is:
B
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An organic compound 'A' is oxidized with Na_(2)O_(2) followed by boiling with HNO_(3) . The resultant solution is then treated with ammonium molybdate to yield a yellow precipitate. Based on above observation,the element present in the given compound is :

X+HNO_(3) to Y+NO_(2)+H_(2)O+S , Y+Ammonium molybdate to yellow ppt. identify X:

Knowledge Check

  • A compound X react with Na_(2)O_(2) and forms Y , Y is reacted with nitric acid and then treated with ammonium molybdate to give yellow ppt.

    A
    Phosphorus
    B
    Nitrogen
    C
    Fluorine
    D
    Sulphur

  • On heating an organic compound with dry CuO, a gas is liberated which turns the line water milky . The gas is ______.

    A
    `H_(2)`
    B
    `O_(2)`
    C
    `CO_(2)`
    D
    `N_(2)`

  • An organic compound on heating with CuO produces CO_(2) but no water. It may be:

    A
    `CH_(4)`
    B
    `C_(2)H_(5)I`
    C
    `CHCI_(3)`
    D
    `C CI_(4)`

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    Which of the following compounds on reaction with Na_(2)O_(2) gives yellow colour?

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