The efficiency of an ideal heat engine working between the freezing point and boiling point of water, is

Options

A. `6.25%`
B. `12.5%`
C. `20 %`
D. `26.8%`

Answer

D

Explanation

`eta = 1 - (T_(2))/(T_(1)) = 1 - (273)/(373) = (100)/(373) = (100 xx 100)/(373) = 26.8%`