The readings corresponding to the ice point and steam point for a constant pressure gas thermometer are `500 cc`, and `545 cc`. If the reading corresponding to room temperature be `510 cc`, find the room temperature ?

Explanation

Given : `V_(0) = 500c c, V_(100) = 545c c` and `V_(t) = 510c c`,
Using, `t = [(V_(t)-V_(0))/(V_(100)-V_(0))] xx 100 = [(510-500)/(545-500)]100`
`= 22.22^(@)C`