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An air bubble of volume V(0) is released...

An air bubble of volume `V_(0)` is released by a fish at a depth `h` in a lake. The bubble rises to the surface. Assume constant temperature and standard atmospheric pressure `P` above the lake. The volume of the bubble just before reaching the surface is
(`d` is the density of water).

A

`V_(0) + (hgd)/(P)`

B

`(V_(0)(P + hgd))/(P)`

C

`(V_(0))/(P) + hgd`

D

`(V_(0) + V_(0)dg)`

Text Solution

Verified by Experts

The correct Answer is:
B
`P_(1)V_(1) = P_(2)V_(2) , (P + hdg)V_(0) = PV`
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