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The tota energy of a particle executing ...

The tota energy of a particle executing simple harmonic motion is `16J`. What will be total energy of particle if amplitude is halved and frequency is douboled?

A

`1J`

B

`64 J`

C

`16J`

D

`256J`

Text Solution

Verified by Experts

The correct Answer is:
C
`T.E. = (1)/(2) m omega^(2) A^(2)`
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