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For a transistor the value of alpha is 0...

For a transistor the value of `alpha` is `0.9`. `beta` value is

A

`9`

B

`0.9`

C

`0.09`

D

`90`

Text Solution

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The correct Answer is:
To find the value of `beta` for a transistor given that `alpha` is `0.9`, we can use the relationship between `alpha` and `beta`. The relationship is given by the formula: \[ \beta = \frac{\alpha}{1 - \alpha} \] ### Step-by-Step Solution: 1. **Identify the given value of alpha**: - We know that \( \alpha = 0.9 \). 2. **Substitute alpha into the formula**: - Plug the value of \( \alpha \) into the formula for \( \beta \): \[ \beta = \frac{0.9}{1 - 0.9} \] 3. **Calculate the denominator**: - Calculate \( 1 - 0.9 \): \[ 1 - 0.9 = 0.1 \] 4. **Perform the division**: - Now substitute back into the equation: \[ \beta = \frac{0.9}{0.1} \] 5. **Calculate the final value of beta**: - Perform the division: \[ \beta = 9 \] ### Final Answer: The value of \( \beta \) is \( 9 \). ---

To find the value of `beta` for a transistor given that `alpha` is `0.9`, we can use the relationship between `alpha` and `beta`. The relationship is given by the formula: \[ \beta = \frac{\alpha}{1 - \alpha} \] ### Step-by-Step Solution: ...
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