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When a current drawn from a battery is 0...

When a current drawn from a battery is 0.5 A its terminal potential difference is 20 V. And when current drawn from it is 2.0 A, the terminal voltage reduces to 16 V. Find out. `e.m.f` and internal resistance of the bettery.

Text Solution

AI Generated Solution

To solve the problem, we need to find the electromotive force (e.m.f) and the internal resistance of the battery using the given data. We will use the formula for terminal voltage, which is given by: \[ V = E - I \cdot r \] where: - \( V \) is the terminal voltage, - \( E \) is the e.m.f of the battery, - \( I \) is the current flowing through the circuit, ...
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Knowledge Check

  • As the current drawn from the cell increases, terminal potential difference of a cell is

    A
    constant
    B
    decreases
    C
    increases
    D
    none of these
  • When current supplied by a cell to a circuit is 0.3 A, its terminal potential difference is 0.9 V. When the current supplied becomes 0.25 A, its terminal potential difference becomes 1.0 V. The internal resistance of the cell is .

    A
    ` 0.5 Omega`
    B
    `2 Omega`
    C
    `1.2 Omega`
    D
    `1 Omega`
  • When current supplied by a cell to a circuit is 0.3 A , its terminal potential difference is 0.9 A. When the current supplied becomes 0.2 A, its terminal potential difference becomes 1.0 V . The internal resistance of the cell is

    A
    `0.5 Omega`
    B
    `2Omega`
    C
    ` 1.2 Omega`
    D
    `1 Omega `
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    When a bettery is connected to the resistance of 10Omega the current in the circuit is 0.12 A the same battery gives 0.07A current with 20Omega calculate e.m.f and internal resistance of the battery.

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