If the electron in a Hydrogen atom makes `6.25xx10^(15)` revolutions in one second, the current is

Options

A. `1.12mA`
B. `1mA`
C. `1.25mA`
D. `1.5mA`

Explanation

To find the current generated by an electron in a hydrogen atom making \(6.25 \times 10^{15}\) revolutions per second, we can follow these steps:

### Step 1: Understand the relationship between current, charge, and time
The current \(I\) is defined as the rate of flow of charge. Mathematically, it can be expressed as:
\[ I = \frac{Q}{t} \]
where \(Q\) is the charge and \(t\) is the time.

### Step 2: Relate charge to frequency
In this case, the electron makes \(6.25 \times 10^{15}\) revolutions per second, which can be considered as the frequency \(f\) of the electron's motion:
\[ f = 6.25 \times 10^{15} \text{ Hz} \]
The total charge \(Q\) that passes through a point in one complete cycle (one revolution) is equal to the charge of one electron, which is approximately:
\[ Q = 1.6 \times 10^{-19} \text{ C} \]

### Step 3: Calculate the current
Since the electron completes \(6.25 \times 10^{15}\) revolutions in one second, the current can be calculated by multiplying the charge of the electron by the frequency:
\[ I = Q \times f \]
Substituting the values:
\[ I = (1.6 \times 10^{-19} \text{ C}) \times (6.25 \times 10^{15} \text{ Hz}) \]

### Step 4: Perform the multiplication
Now, we can calculate:
\[ I = 1.6 \times 6.25 \times 10^{-19} \times 10^{15} \]
Calculating \(1.6 \times 6.25\):
\[ 1.6 \times 6.25 = 10.0 \]
Thus:
\[ I = 10.0 \times 10^{-4} \text{ A} \]
This can be expressed in milliamperes (mA):
\[ I = 1.0 \text{ mA} \]

### Conclusion
The current flowing due to the electron in the hydrogen atom is:
\[ \boxed{1.0 \text{ mA}} \]