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The maximum distance between the transmi...

The maximum distance between the transmitting and receving TV towers is `64 km`. If the ratio of the heights of the TV transmitting tower to receiving tower is `4 : 9`, the heights of the transmitting and receiving tower are

A

`51.2 m`, `80m`

B

`1280m`, `2880m`

C

`80m`, `125m`

D

`25m`, `75m`

Text Solution

Verified by Experts

The correct Answer is:
B
`d=sqrt(2Rh_(T))+sqrt(2Rh_(R))`, `(h_(T))/(h_(R))=(4)/(9)`, `d=64km`
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Knowledge Check

  • The maximum distance between the transmitting and receving TV towers is 72 km . If the ratio of the heights of the TV transmitting tower to receiving tower is 16 : 25 , the heights of the transmitting and receiving tower are

    A
    `51.2m`, `80m`
    B
    `40 m` , `80 m`
    C
    `80 m`, `125 m`
    D
    `25 m` , `75 m`

  • If h_(T) and h_(R) are the height of the transmitting and receiving antennas above the earth's surface and R is the radius of earth, then distance between the transmitting and receiving antenna is

    A
    `sqrt((2h_(R)+2h_(T))R)`
    B
    `sqrt(2Rh_(T))+sqrt(2Rh_(R))`
    C
    `sqrt(((h_(T))/(h_(R)))R)`
    D
    `sqrt(((h_(T)^(2)+h_(R)^(2)))/(R))`

  • If the area to be covered for TV telecast is doubles then height of transmitting antenna (TV tower) will have to be:

    A
    doubled
    B
    halved
    C
    quardupled
    D
    kept unchanged

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