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A cell of emf E and internal resistance ...

A cell of emf `E` and internal resistance `r` connected in the secondary gets balanced against length `l` of potentiometer wire. If a resistance `R` is connected in parallel with the cell, then the new balancing length for the cell will be

A

`((R)/(R-r))`

B

`((R-r)/(R))`

C

`((R)/(r))`

D

`((R)/(R+r))l`

Text Solution

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The correct Answer is:
D
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