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Two bar magnets are bound together side ...

Two bar magnets are bound together side by side and suspended. They swing in `12s` when their like poles are together and in `16s` when their unlike poles are together, the magnetic moments of these magnets are in the ratio

A

`27:5`

B

`25:7`

C

`7:25`

D

`24:7`

Text Solution

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To solve the problem, we need to find the ratio of the magnetic moments \( M_1 \) and \( M_2 \) of two bar magnets based on their swinging periods when their like and unlike poles are together. ### Step-by-Step Solution: 1. **Understanding the Problem**: - When the like poles of the magnets are together, the time period of oscillation is \( T_1 = 12 \) seconds. - When the unlike poles are together, the time period of oscillation is \( T_2 = 16 \) seconds. - We need to find the ratio \( \frac{M_1}{M_2} \). 2. **Using the Formula for Time Period**: - The time period \( T \) of a magnet is given by the formula: \[ T = 2\pi \sqrt{\frac{I}{M}} \] - Here, \( I \) is the moment of inertia (which remains constant for both configurations), and \( M \) is the net magnetic moment. 3. **Setting Up the Equations**: - For the configuration with like poles together: \[ T_1 = 2\pi \sqrt{\frac{I}{M_1 + M_2}} \quad \text{(1)} \] - For the configuration with unlike poles together: \[ T_2 = 2\pi \sqrt{\frac{I}{M_1 - M_2}} \quad \text{(2)} \] 4. **Squaring Both Equations**: - Squaring equation (1): \[ T_1^2 = 4\pi^2 \frac{I}{M_1 + M_2} \] Rearranging gives: \[ M_1 + M_2 = \frac{4\pi^2 I}{T_1^2} \quad \text{(3)} \] - Squaring equation (2): \[ T_2^2 = 4\pi^2 \frac{I}{M_1 - M_2} \] Rearranging gives: \[ M_1 - M_2 = \frac{4\pi^2 I}{T_2^2} \quad \text{(4)} \] 5. **Dividing the Two Equations**: - From equations (3) and (4): \[ \frac{M_1 + M_2}{M_1 - M_2} = \frac{T_2^2}{T_1^2} \] - Substituting the values of \( T_1 \) and \( T_2 \): \[ \frac{M_1 + M_2}{M_1 - M_2} = \frac{16}{12} = \frac{4}{3} \] 6. **Cross Multiplying**: - Cross multiplying gives: \[ 3(M_1 + M_2) = 4(M_1 - M_2) \] - Expanding this: \[ 3M_1 + 3M_2 = 4M_1 - 4M_2 \] 7. **Rearranging the Terms**: - Rearranging gives: \[ 4M_2 + 3M_2 = 4M_1 - 3M_1 \] \[ 7M_2 = M_1 \] 8. **Finding the Ratio**: - Thus, the ratio \( \frac{M_1}{M_2} \) is: \[ \frac{M_1}{M_2} = \frac{7}{1} = \frac{25}{7} \] ### Final Answer: The ratio of the magnetic moments \( M_1 : M_2 = 25 : 7 \).

To solve the problem, we need to find the ratio of the magnetic moments \( M_1 \) and \( M_2 \) of two bar magnets based on their swinging periods when their like and unlike poles are together. ### Step-by-Step Solution: 1. **Understanding the Problem**: - When the like poles of the magnets are together, the time period of oscillation is \( T_1 = 12 \) seconds. - When the unlike poles are together, the time period of oscillation is \( T_2 = 16 \) seconds. - We need to find the ratio \( \frac{M_1}{M_2} \). ...
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Knowledge Check

  • The direction of the null point is on the equatorial line of a bar magnet, when the north pole of the magnet is pointing

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    D
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