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A cylindrical rod magnet has a length of...

A cylindrical rod magnet has a length of 5 cm and a diameter of 1 cm. It has a unifirm magnetisation of `5.30xx10^(3) Amp//m^(3)`. What its magnetic dipole moment?

A

`20.8mJT^(-1)`

B

`10.8mJT^(-1)`

C

`5.8mJT^(1)`

D

`30.8mJT^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
`M(m)/(V)` or `m=MV`
`m=Mxx(pi r^(2)l)`
`=(5.3xx10^(3))(3.14)(5xx10^(-3))^(2)(5xx10^(-2))J//T =20.8xx10^(-3)J//T=20.8mJ//T`
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