In the propagation of polarised light waves, the angle between the plane of vibration and the plane of polarization is

Options

A. `0^(@)`
B. `90^(@)`
C. `45^(@)`
D. `180^(@)`

Answer

To solve the question regarding the angle between the plane of vibration and the plane of polarization in the propagation of polarized light waves, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding the Terms**:
- **Plane of Vibration**: This refers to the plane in which the electric field vector of the light wave oscillates. For a transverse wave like light, the vibration occurs perpendicular to the direction of wave propagation.
- **Plane of Polarization**: This is defined as the plane that contains the electric field vector and is perpendicular to the direction of wave propagation.

2. **Direction of Propagation**:
- In an electromagnetic wave, the direction of propagation is perpendicular to both the electric field vector (E) and the magnetic field vector (B). If we consider the wave propagating in the z-direction, the electric field vector can lie in the x-y plane.

3. **Identifying the Planes**:
- If we assume the electric field vector oscillates in the x-direction, then the plane of vibration is the x-z plane (where the electric field oscillates).
- The plane of polarization, which is parallel to the electric field vector, will be the x-y plane.

4. **Calculating the Angle**:
- The angle between the plane of vibration (x-z plane) and the plane of polarization (x-y plane) can be determined by visualizing these two planes.
- Since the x-z plane and x-y plane are perpendicular to each other, the angle between them is 90 degrees.

5. **Conclusion**:
- Therefore, the angle between the plane of vibration and the plane of polarization is 90 degrees.

### Final Answer:
The angle between the plane of vibration and the plane of polarization is **90 degrees**.

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