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Which of the following expressions is co...

Which of the following expressions is correct?

A

`DeltaG=DeltaG^(Θ)+RT 1n Q`

B

`DeltaG^(Θ)=-RT1nK_(eq)`

C

`K_(eq)=e^(-DeltaG^(Θ)//RT`

D

All of these

Text Solution

Verified by Experts

The correct Answer is:
D
`DeltaG=DeltaG^(Θ)+RT 1nQ`
At equilibrium, `DeltaG=0` and `Q=K_(eq)`
`:. 0=DeltaG^(Θ)+RT 1n K_(eq)`
`DeltaG^(Θ)=-RT1nK_(eq)`
`1n K_(eq)=(-DeltaG^(Θ))/(RT)`
Taking the antilog of both sides, we get
`K_(eq)=e^(-DeltaG^(Θ)//RT)`
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