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AIF(2) is soluble in HF only in presence...

`AIF_(2)` is soluble in `HF` only in presence of `KF`. It is due to the formation of

A

`K_(3)[AlF_(3)H_(3)]`

B

`K_(3)[AlF_(6)]`

C

`AIH_(3)`

D

`K[AlF_(3)H]`

Text Solution

Verified by Experts

The correct Answer is:
2
Aluminium trifluorde is insoluble in anhydroous `HF` but dissoves on additon of `KF` beacause anhydrous `HF` is a covalent compound and is strongly `H-`bonded. Therefore, it does not yield `F^(-)` ion and hence `AlF_(3)` does not dissolve in `HF`. On the other hand, `KF` being an ionic compound contains `F^(-)` ions and hence combines with `AlF_(3)` to form the complex, thereby shifitng the equilibrium:
`underset("Insoluble")(AlF_(3))(s) overset(HF)(hArr) AlF_(3)(HF) overset(KF)(rarr) underset(("soluble complex"))underset("Pot. hexafluridoalumunate (III)")`
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Knowledge Check

  • AlF_(3) soluble in HF only in presence of KF. It is due to the formation of

    A
    `K_(3)[AlF_(3)H_(3)]`
    B
    `K_(3)[AlF_(6)]`
    C
    `AlH_(3)`
    D
    `Kl[AlF_(3)H]`

  • AgCl is soluble in NHpH solution. The solubility is due to the formation of

    A
    `AgOH`
    B
    `Ag_(2)O`
    C
    `[Ag(NH_(3))_(2)]^(+)`
    D
    `NH_(4)Cl`

  • AgCl is soluble in NH_(4)OH solution. The solubility is due to the formation of

    A
    AgOH
    B
    `Ag_(2)O`
    C
    `[Ag(NH_(3))_(2)]^(+)`
    D
    `NH_(4)Cl`+NHOH

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