An electric dipole is formed two particles fixed at the ends of a light rad of length `I`. The mass of each particle is `m` and charges are `-q` and `+q`The system is suspended by a torsionless thread in an electric field of intensity `E` that the dipole axis is parallel to the field if it is slightly displaced the period of angular motion is

Options

A. `(1)/(2pi)sqrt((2qE)/(ml))`
B. `2pisqrt((2ml)/(qE))`
C. `2pisqrt((ml)/(2qE))`
D. `(1)/(2pi)sqrt((ml)/(4qE))`

Answer

3

Explanation

`t=PEsintheta,tau=lalpha,Ialpha=PEsintheta`
`I="moment of inertia" =`(ml^(2))/(2)`
`:. "Time period"=`2pisqrt((I)/(PE))`