A steady `P.D` of `10 V` produces heat at a rate `'x'` in resistor. The peak value of `A.C` voltage which will produce heat at rate of `x//2` is same resistor is

Options

A. `5 V`
B. `5 sqrt(2)`
C. `10 V`
D. `10 sqrt(2) V`

Answer

3

Explanation

`(v^(2))/(R ) = x, (v_(1)^(2))/(R ) = (x)/(2) implies v_(1) = (v)/(sqrt(2))`
`:.` in the second case `V_("rms") = V_(1) :. V_(0) = sqrt(2) V_(1)`