In a series `LCR` circuit the voltage across the resistance, capacitance and inductance is `10` V each. If the capacitance is short circuited, the voltage across the inductance will be `(10^(x))/(sqrt(2))` what is value of x

Answer

1

Explanation

the source voltage is
`V=sqrt(10^(2)+(10-10)^(2))=10 V`
After capacitor is short circuited, let `V_(1)` be voltage across each of inductor, resistor
`therefore 10=sqrt(V_(1)^(2)+V_(1)^(2))=sqrt2V_(1) , V_(1)=(10)/(sqrt2)`