Calculate the amount of heat energy to be supplied to convert 2 kg of ice at `0^@C` completely into water at`0^@C` if latent heat of fusion for ice is 80 cal/g.

Answer

Heat energy to be supplied is 160 kcal.

Explanation

Given Mass (m) `=2 kg =2 xx 10^3 g`, latent
heat of fusion for ice (L) = 80 cal /g .
To find , Heat energy (Q)
Formula : Q=mL
Calculation: Formula formula,
`Q= 2 xx 10^3 xx 80 = 160000 cal `
= 160 kcal .