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KMnO(4) in basic medium is reduced to...

`KMnO_(4)` in basic medium is reduced to

A

`K_(2)MnO_(4)`

B

`MnO_(2)`

C

`Mn(OH)_(2)`

D

`Mn^(2+)`

Text Solution

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The correct Answer is:
B
`KMnO_(4)` is first reduced to manganate and then to isoluble manganese dioxide. Colour changes first from purple to green and finally becomes colourless.
`{:(2KMnO_(4)+2KOHrarr2K_(2)MnO_(4)+4_(2)O+O),(2K_(2)MnO_(4)+2H_(2)Orarr2MnO_(2)+4KOH+2O),(bar(2KMnO_(4)+H_(2)Ooverset("alkaline")rarr2MnO_(2)+2KOPH+3[O])):}`
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KMnO_(4) in basic medium is used as

Assertion :- Equivalent weight of KMnO_(4) in acidic medium is M//5 (M=molecular weight) while in basic medium, it is equal of M/3. Reason :- In acidic medium, 1 mol of MnO_(4)^(-) gains 5 mole electrons while in basic medium it gains 3 mole electrons.

The molarity (m) of KMnO_(4) in the acidic medium is (densityh of KMnO_(4) solution =1.58gmL^(-1)Mw(KMnO_(4))=158gmol^(-1))

KMnO_(4) reacts with KI in basic medium to from I_(2) and MnO_(2) . When 250 mL of 0.1 M KI solution is mixed with 250 mL of 0.02 M KMnO_(4) in basic medium, what is the number of moles I_(2) formed ?

100mL of H_2O_2 is oxidised by 100mL of 0.01M KMnO_4 in acidic medium (MnO_4^(ɵ) reduced to Mn^(2+) ). 100mL of the same H_2O_2 is oxidised by VmL of 0.01M KMnO_4 in basic medium. Hence V is

Molecular weight of KMnO_(4) in acidic medium and neutral medium will be respecitvely -

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