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An organic compound undergoes first deco...

An organic compound undergoes first decompoistion. The time taken for its decompoistion to `1//8` and `1//10` of its initial concentration are `t_(1//8)` and `t_(1//10)`, respectively. What is the value of `([t_(1//8)])/([t_(1//10)]) xx 10`? `(log_(10)2 = 0.3)`

Text Solution

Verified by Experts

The correct Answer is:
9
For a first order reaction,
`k=(2*303)/t"log"C_0/C_t" or "t=(2*303)/k"log"C_0/C_t`
`:." "1_(1//8)=(2*303)/t"log"C_0/(C_0//8)=(2*303)/k"log 8"`
`=(2*303)/k"log 2"^3=(2*303xx3)/k"log 2"`
`=(2*303xx3xx0*3)/k`
`t_(1//2)=(2*303)/k"log"C_0/(C_0//10)=(2*303)/k" log 10"=(2*303)/k`
`:." "t_(1//8)/t_(1//10)=3xx0*3=0*9" or "t_(1//8)/(t_(1//10))" or "t_(1//8)/t_(1//10)xx10=9`
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An organic compound undergoes first-order decomposition . The time taken for its decomposition to 1/8 and 1/10 of its initial concentration are t_(1//8) and t_(1//10) respectively . What is the value of ([t_(1//8)])/([t_(1//10)]) xx 10 (take log_(10) 2 = 0.3 )

An organic compound undergoes first order decomposition. The time taken for the decomposition of 1//8 and 1//10 of its initial concentration are 1//8 and 1//10 respectively. What is the value of [t_(1//8)]/([t_(1//10)]) xx 10 (take log_(10)2=0.3)

Knowledge Check

  • An organic compound undergoes first order decomposition . The time taken for its decomposition to 1/8 and 1/10 of its initial concentration are t_(1//8) and t_(1//10) respectively. What is the value of ([t_(1//8)])/([t_(1//10)]) ? (take log_(10)2=0.3 )

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