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For a reaction AtoB, the rate of reactio...

For a reaction `AtoB`, the rate of reaction can be denoted by `-(dA)/(dt)" or "+(dB)/(dt)`. State the significance of plus and minus signs in this case.

Answer

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Knowledge Check

  • For the reaction 3A to 2R , rate of reaction + (d[B])/(dt) is equal to:

    A
    `(-3)/2 (d[A])/(dt)`
    B
    `-2/3 (d[A])/(dt)`
    C
    `(-1)/3 (d[A])/(dt)`
    D
    `+2 (d[A])/(dt)`

  • If for the reaction A to B" rate" =-(d[A])/(dt)=2(d[B])/(dt) then, rate law is

    A
    `-(d[A])/(dt)=k[A]^(2)`
    B
    `(d[B])/(dt)=k[A] `
    C
    `(d[A])/(dt)=k[A]^(2)`
    D
    `-(d[B])/(dt)=k[B]^(2)`

  • For a hypothetical reaction, A rarr L the rate expression is rate =-(dC_(A))/(dt)

    A
    negative sign represents that rate is negative
    B
    negative sign pertains to the decrease in the concentrations of reactants
    C
    negative sign indicates the attractive forces between reactants
    D
    none of the above is correct

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    The expression for the induced e.m.f. contains a negative sign [e=-(dphi)/(dt)] . What is the significance of the negative sign?

    In the reaction, 3A rarr 2B rate of reaction, +(d[B])/(dt) is equal to

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