Why is the `C-O-H` bond angle in alcohols slightly less than the tetrahedral angle whereas the C-O-C bond angle in ether is slightly greater?

Explanation

The oxygen atom in both alcohols and ethers in `sp^(3)`-hydridized. However, due to greater

lone pair-lone pair than bond pair-bond pairr repulsion, the C-O-H bond angle in alcohols is slightly lowerr `(109^(@))` than the normal tetrahderal angle of `109^(@)-28'`. however, in ether C-O-C bond angle is slightly greater `(110^(@))` than tetrahedral angle due to repulsion between the two bulkyl R groups.