Assertion: Phenoxide ion on treatment with active alkyl halide (e.g., `CH_(2)=CH_(2)-CH_(2)Cl`) gives two products, viz. , O-substituted annd C-substituted.
Reason: Phenoxide ion is an ambident nuleophile.

Options

A. If both assertion and reason are true, and reason is the true explanation of the assertion.
B. If both assertion and reason are true, but reason is not the true explanation o the assertion.
C. if assertion is true, but reason is false.
D. If both assertion and reason are false.

Answer

To solve the question regarding the assertion and reason about the phenoxide ion and its reaction with an active alkyl halide, we can follow these steps:

### Step 1: Understand the Assertion
The assertion states that the phenoxide ion, when treated with an active alkyl halide like `CH2=CH2-CH2Cl`, produces two products: O-substituted and C-substituted.

### Step 2: Analyze the Reaction
Phenoxide ion (C6H5O^-) is a strong nucleophile due to the negative charge on the oxygen atom. When it reacts with an alkyl halide, it can potentially attack either the carbon atom (C-substitution) or the oxygen atom (O-substitution).

### Step 3: Identify the Products
1. **O-Substitution**: The phenoxide ion can attack the alkyl halide at the oxygen atom, leading to the formation of an ether (O-substituted product).
2. **C-Substitution**: The phenoxide ion can also attack the carbon atom of the alkyl halide, leading to the formation of a carbon-substituted product.

### Step 4: Evaluate the Reason
The reason states that the phenoxide ion is an ambident nucleophile, which means it can attack at two different sites (the oxygen or the carbon). However, in this case, the reaction conditions and the nature of the alkyl halide influence the outcome.

### Step 5: Conclusion
While the assertion claims that both O-substituted and C-substituted products are formed, the reaction with an active alkyl halide typically favors O-substitution due to the stability of the resulting ether. Therefore, the assertion is not entirely correct. The reason also does not hold true in this context as the phenoxide ion primarily acts as a nucleophile at the oxygen site in this reaction.

### Final Answer
Both the assertion and the reason are false. The phenoxide ion primarily leads to O-substituted products when reacting with active alkyl halides.