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Match the following {:("(i)","88 g of ...

Match the following
`{:("(i)","88 g of CO"_(2),"(a)","0.25 mol"),("(ii)",6.022 xx 10^(23)" molecules of "H_(2)O,"(b)","2 mol"),("(iii)","5.6 litres of O"_(2)" at STP","(c)","1 mol"),("(iv)","96 g of O"_(2),"(d)",6.022xx10^(23)"molecules"),("(v)","1 mole of any gas","(e)","3 mol"):}`

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Verified by Experts

The correct Answer is:
(i)-(b), (ii)-(c), (iii)-(a), (iv)-(e), (v)-(d)
`"88 g CO"_(2)="88/88 mol = 2 mol. Hence, (i)-(b)."`
`6.022xx10^(23)" molecules of "H_(2)O="1 mol. Hence, (ii)-(b)"`
`"5.6 L of O"_(2)" at STP = 5.6/22.4 mol = 0.25 mol. Hence, (iii)-(a)"`
`"96 go of O"_(2)=" 96/32 mol = 3 mol. Hence, (iv)-(e)."`
`"1 mol of any gas"=6.022xx10^(23)" molecules. Hence, (v)-(d)"`
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