Find the equivalent spring constant in the following cases:

Explanation

Solution:
(a). `k_(eq)=k+2k=3k`
(b) `k_(eq)=k+2k=3k`
(c) `(1)/(k_(eq))=(1)/(3k)+(1)/(6k)impliesk_(eq)=2k`
(d). `(1)/(k_(eq))=(1)/(8k)+(1)/(12k)+(1)/(24k)impliesk_(eq)=4k`
(e). 3k and 6k are series
`(1)/(k')=(1)/(3k)+(1)/(6k)impliesk'=2k`
`k'` and 2k are parallel
`k_(eq)=k'+2k=4k`