Two blocks of masses 5 kg and 10 kg are connected by a massless spring as shown in the diagram. A force of 100 N acts on 10kg mass as shown. At a certain instant the acceleration of 5 kg mass is 12 `m//s^(2)` find the force in the spring and acceleration of 10 kg mass.

Explanation

for 5 kg mass `T=5xx12=60N`
For 10 kg mass `100-T=10a`
`100-60=10a`
`a=4m//s^(2)`