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1.375 g of cupric oxide was reduced by h...

`1.375 g` of cupric oxide was reduced by heating in a current of hydrogen and the weight of copper that remained was `1.098 g` In another experiment, `1.179 g` of copper was dissolved in nitric acid and the resulting copper nitrate converted into cupric oxide by ignition. The weight of cupric oxide formed was `1.476 g`. Show that these result illustrate the law of constant composition.

Text Solution

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`{:("Ist exp",,CuO=1.375gm),(,,Cu=1.098gm),(,,O=0.277gm),("IInd exp".,,Cu=1.179gm),(,,CuO=1.4476 gm),(,,O=0.2686gm):}`
`(Cu)/(O) = 3.9638=4 " "(Cu)/(O)=4`
In both the cases ratio of `Cu//O` is same
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2,75 g of cupric oxide was reduced by heating in a current of hydrogen and the weight of copper that remained was 2.196 g. Another experiment, 2.358 g of copper was dissolved in nitric acid and the resulting copper nitrate converted into cupric oxide by ignition. The weight of cupric oxide formed was 2.952 g. Show that these results illustrate law of constant composition.

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Knowledge Check

  • 4 g of copper was dissolved in concentrated nitric acid. The copper nitrate on strong heating gave 5 g of its oxide. The equivalent weight of copper is

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    B
    32
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    23
    B
    32
    C
    12
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    20
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